Step 1: Identifying the first reaction. The first step involves Friedel-Crafts Alkylation, where \( {CH}_3X \) (an alkyl halide) reacts with benzene (\( {C}_6{H}_6 \)) in the presence of \( {AlCl}_3 \), forming toluene (A) (\( {C}_6{H}_5{CH}_3 \)). \[ {C}_6{H}_6 + {CH}_3X \xrightarrow{{AlCl}_3} {C}_6{H}_5{CH}_3 \]
Step 2: Oxidation of Toluene. - The second step involves oxidation using chromyl chloride (\({CrO}_2Cl_2\)), known as the Etard Reaction, which selectively oxidizes the methyl group (\(-{CH}_3\)) to an aldehyde (\(-{CHO}\)), forming benzaldehyde (B) (\({C}_6{H}_5{CHO}\)). \[ {C}_6{H}_5{CH}_3 \xrightarrow{{CrO}_3 { in } (CH_3CO)_2O / H_3O^+} {C}_6{H}_5{CHO} \]
Step 3: Eliminating incorrect Option.
- Acetophenone (A) (\({C}_6{H}_5{COCH}_3\)): Incorrect, as the oxidation of toluene in the Etard reaction leads to the formation of an aldehyde (\({C}_6{H}_5{CHO}\)) and not a ketone.
- Cyclohexyl carbaldehyde (C) (\({C}_6{H}_{11}{CHO}\)): Incorrect, as the reaction occurs on a benzene ring, not on a cyclohexane system, and no such transformation takes place.
- Benzoic acid (D) (\({C}_6{H}_5{COOH}\)): Incorrect, as oxidation of the methyl group (\(-{CH}_3\)) to a carboxyl group (\(-{COOH}\)) requires a stronger oxidizing agent such as alkaline \({KMnO}_4\) or acidic \({K}_2{Cr}_2{O}_7\) under reflux, which is not used in this reaction.
Thus, the correct answer is (B) Benzaldehyde (\({C}_6{H}_5{CHO}\)).
If the CFSE of $\left[ Ti \left( H _2 O \right)_6\right]^{3+}$ is $-960 kJ / mol$, this complex will absorb maximum at wavelength ___$nm$ (nearest integer) Assume Planck's constant $( h )=64 \times 10^{-34} Js$, Speed of light $( c )=30 \times 10^8 m / s$ and Avogadro's Constant $\left( N _{ A }\right)=6 \times 10^{23} / mol$
Evaluate the following limit: $ \lim_{n \to \infty} \prod_{r=3}^n \frac{r^3 - 8}{r^3 + 8} $.
In the given cycle ABCDA, the heat required for an ideal monoatomic gas will be: