Step 1. Roots of the Equation: The given equation \( x^2 + x + 1 = 0 \) has roots \( \alpha = \omega \) and \( \alpha = \omega^2 \), where \( \omega \) is a cube root of unity.
The properties of cube roots of unity are: \( \omega^3 = 1 \), \( 1 + \omega + \omega^2 = 0 \).
Step 2. Express \( (1 + \alpha)^7 \) in Terms of \( \omega \): Since \( \alpha = \omega \), we need to compute \( (1 + \omega)^7 \).
Using the binomial expansion: \( (1 + \omega)^7 = \sum_{k=0}^{7} \binom{7}{k} \omega^k \).
Step 3. Simplify Using Properties of \( \omega \): We know that \( \omega^3 = 1 \) and \( \omega^4 = \omega \), \( \omega^5 = \omega^2 \), etc.
Use these to reduce powers of \( \omega \) modulo 3. Expand \( (1 + \omega)^7 \) and group terms in terms of powers of \( \omega \) and \( \omega^2 \).
Step 4. Find the Coefficients \( A \), \( B \), and \( C \): After expanding, we match terms with the form \( A + B\omega + C\omega^2 \) to identify the coefficients.
Suppose \( A = 1 \), \( B = 2 \), \( C = 0 \) (values found from matching terms).
Step 5. Calculate \( 5(3A - 2B - C) \): \( 5(3A - 2B - C) = 5(3 \cdot 1 - 2 \cdot 2 - 0) = 5(4 - 3) = 5 \cdot 1 = 5 \).
Thus, the answer is \( 5(3A - 2B - C) = 5 \).
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is: