Question:

If for the series \(a_1, a_2, a_3, \ldots\), etc., \(a_{n+1} - a_n\) bears a constant ratio with \(a_n + a_{n+1}\), then \(a_1, a_2, a_3, \ldots\) are in:

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In problems where the difference between terms has a constant ratio with the sum of consecutive terms, the series is typically a harmonic progression (H.P.).
Updated On: Jan 10, 2025
  • A.P.
  • G.P.
  • H.P.
  • Any other series
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The Correct Option is C

Solution and Explanation

Step 1: Given that the difference between consecutive terms \( a_{n+1} - a_n \) bears a constant ratio with the sum of consecutive terms \( a_n + a_{n+1} \), we express this as:

\[ \frac{a_{n+1} - a_n}{a_{n+1} + a_n} = k \]

where \( k \) is a constant ratio.

Step 2: Rearranging this equation:

\[ a_{n+1} - a_n = k(a_{n+1} + a_n) \]

Step 3: Simplifying:

\[ a_{n+1} - a_n = k a_{n+1} + k a_n \] \[ a_{n+1} - k a_{n+1} = a_n + k a_n \] \[ a_{n+1}(1 - k) = a_n(1 + k) \]

Step 4: Solving for \( a_{n+1} \):

\[ a_{n+1} = \frac{1 + k}{1 - k} a_n \]

This is a characteristic property of a series where the ratio between consecutive terms is constant. This behavior corresponds to a harmonic progression (H.P.), because the general term \( a_n \) satisfies the relation of terms being inversely proportional to an arithmetic progression.

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