Step 1: Understanding the Problem
1. When the escalator is stationary, Ruma walks with a velocity \( v_1 \) and takes time \( t_1 \) to reach the top. The height \( h \) of the escalator can be related to the time and velocity:
\[
h = v_1 \cdot t_1
\]
2. When the escalator is moving with velocity \( v_2 \), and Ruma is stationary on the escalator, the time taken to reach the top is \( t_2 \). The total velocity of Ruma on the moving escalator is \( v_2 \) and the distance \( h \) is covered in time \( t_2 \):
\[
h = v_2 \cdot t_2
\]
Step 2: Time to Walk Up the Moving Escalator
If Ruma is walking with velocity \( v_1 \) on the moving escalator, her effective velocity will be \( v_1 + v_2 \) (since both velocities add up when moving in the same direction). The time \( t_3 \) taken to cover the distance \( h \) will be:
\[
t_3 = \frac{h}{v_1 + v_2}
\]
Step 3: Substituting Values for \( h \)
From the equations above for \( h \), we substitute \( h \) from both the cases (stationary escalator and moving escalator) into the equation for \( t_3 \):
\[
t_3 = \frac{v_1 \cdot t_1}{v_1 + v_2}
\]
Step 4: Conclusion
The time taken by Ruma to walk up with velocity \( v_1 \) on the moving escalator is given by:
\[
t_3 = \frac{t_1 \cdot v_1}{v_1 + v_2}
\]
Now, comparing this equation with the given options, we find that the correct choice is Option (C).
Final Answer:
The correct answer is:
\[
\boxed{(C)} \frac{t_1 + t_2}{v_1 + v_2}
\]