\(|A| A\)
For a non singular matrix \(A\), the adjugate of the inverse of \(A\), denoted as \(\text{Adj}(A^{-1})\), can be derived from the relationship: \[ A \cdot \text{Adj}(A) = |A| I \] where \(I\) is the identity matrix and \(|A|\) is the determinant of \(A\). By applying the properties of the adjugate and inverse matrices, and using the formula for the inverse of a product, we have: \[ \text{Adj}(A^{-1}) = \text{Adj}((\text{Adj}(A) \cdot |A|^{-1} I)^{-1}) = (\text{Adj}(A) \cdot |A|^{-1})^{-1} \] Since \(\text{Adj}(A) \cdot |A|^{-1}\) yields \(A^{-1}\), taking the inverse of this expression gives: \[ (\text{Adj}(A) \cdot |A|^{-1})^{-1} = (\text{Adj}(A))^{-1} \cdot |A| I = (\text{Adj}(A))^{-1} \] This leads us to conclude that \(\text{Adj}(A^{-1}) = (\text{Adj} A)^{-1}\), confirming the correct option.
Given matrices \( A \) and \( B \) where:
and the condition:
If matrix \( C \) is defined as:
then the trace of \( C \) is:
$$ \begin{vmatrix} x-2 & 3x-3 & 5x-5 \\ x-4 & 3x-9 & 5x-25 \\ x-8 & 3x-27 & 5x-125 \end{vmatrix} = 0 $$
Calculate the determinant of the matrix:
If \[ \int e^x (x^3 + x^2 - x + 4) \, dx = e^x f(x) + C, \] then \( f(1) \) is:
In Bohr model of hydrogen atom, if the difference between the radii of \( n^{th} \) and\( (n+1)^{th} \)orbits is equal to the radius of the \( (n-1)^{th} \) orbit, then the value of \( n \) is: