Note: \(\sin 70^\circ = \cos 20^\circ\) and \(\sin 10^\circ = \cos 80^\circ\)
Try evaluating numerically:
\[
\frac{1}{2 \cdot \sin 10^\circ} \approx \frac{1}{2 \cdot 0.1736} \approx 2.88,\quad 2 \sin 70^\circ \approx 2 \cdot 0.9397 \approx 1.88
\]
\[
2.88 - 1.88 = 1
\]
So result ≈ 1.