Let's simplify the given circuit.
The circuit consists of three resistors, each with a resistance of $ r/3 $. Let's label them $ R_1 $, $ R_2 $, and $ R_3 $.
We know:
$ \frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} $
$ \Rightarrow \frac{1}{R_p} = \frac{3}{r} + \frac{3}{r} + \frac{3}{r} = \frac{9}{r} $
$ \Rightarrow R_p = \frac{r}{9} $
Final Answer:
The final answer is $ \boxed{r/9} $.