Magnetic Force on a Moving Charge:
When a charged particle, such as an electron, moves in a magnetic field, it experiences a force given by:
\[ \vec{F} = q (\vec{v} \times \vec{B}) \]
where \(\vec{v}\) is the velocity of the particle and \(\vec{B}\) is the magnetic field.
The direction of the force is perpendicular to both \(\vec{v}\) and \(\vec{B}\).
Magnetic Field Inside a Solenoid:
Inside a long solenoid carrying current, the magnetic field \(\vec{B}\) is uniform and directed along the axis of the solenoid.
Since the electron is moving along the axis, its velocity \(\vec{v}\) is also parallel to \(\vec{B}\).
No Magnetic Force Due to Parallel \(\vec{v}\) and \(\vec{B}\):
Since \(\vec{v} \parallel \vec{B}\), the cross product \(\vec{v} \times \vec{B} = 0\).
Therefore, the magnetic force \(\vec{F} = 0\), and the electron will not experience any force due to the magnetic field.
Conclusion:
The electron will continue to move with uniform velocity along the axis of the solenoid, as there is no force acting on it to change its state of motion.
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: