Magnetic Force on a Moving Charge:
When a charged particle, such as an electron, moves in a magnetic field, it experiences a force given by:
\[ \vec{F} = q (\vec{v} \times \vec{B}) \]
where \(\vec{v}\) is the velocity of the particle and \(\vec{B}\) is the magnetic field.
The direction of the force is perpendicular to both \(\vec{v}\) and \(\vec{B}\).
Magnetic Field Inside a Solenoid:
Inside a long solenoid carrying current, the magnetic field \(\vec{B}\) is uniform and directed along the axis of the solenoid.
Since the electron is moving along the axis, its velocity \(\vec{v}\) is also parallel to \(\vec{B}\).
No Magnetic Force Due to Parallel \(\vec{v}\) and \(\vec{B}\):
Since \(\vec{v} \parallel \vec{B}\), the cross product \(\vec{v} \times \vec{B} = 0\).
Therefore, the magnetic force \(\vec{F} = 0\), and the electron will not experience any force due to the magnetic field.
Conclusion:
The electron will continue to move with uniform velocity along the axis of the solenoid, as there is no force acting on it to change its state of motion.
The dimension of $ \sqrt{\frac{\mu_0}{\epsilon_0}} $ is equal to that of: (Where $ \mu_0 $ is the vacuum permeability and $ \epsilon_0 $ is the vacuum permittivity)

Nature of compounds TeO₂ and TeH₂ is___________ and ______________respectively.