The correct answer is \(14W\)
\(R_1=\frac{(220)^2}{100}=484 Ω\), \(R_2=\frac{(220)^2}{60}=\frac{48400}{60} Ω\)
Current (i) 1=\(\frac{220}{484\frac{4840}{6}}=\frac{15}{88}amp\)
\(P_1=\left (\frac{15}{88}\right)^2×484=14.06W=14W\)
The correct answer is \(14W\)
\(R_1=\frac{V^2}{P}=\frac{220^2}{100}=484\)
\(R_2=\frac{V^2}{P}=\frac{220^2}{60}=484(\frac{10}{6})\)
\(I=\frac{220}{484+484\times\frac{10}{6}}\)
\(P_1=I^2R_1=14.06W=14W\)
A battery of emf \( E \) and internal resistance \( r \) is connected to a rheostat. When a current of 2A is drawn from the battery, the potential difference across the rheostat is 5V. The potential difference becomes 4V when a current of 4A is drawn from the battery. Calculate the value of \( E \) and \( r \).
Let $ f: \mathbb{R} \to \mathbb{R} $ be a twice differentiable function such that $$ f''(x)\sin\left(\frac{x}{2}\right) + f'(2x - 2y) = (\cos x)\sin(y + 2x) + f(2x - 2y) $$ for all $ x, y \in \mathbb{R} $. If $ f(0) = 1 $, then the value of $ 24f^{(4)}\left(\frac{5\pi}{3}\right) $ is:
Current electricity is defined as the flow of electrons from one section of the circuit to another.
There are two types of current electricity as follows:
The current electricity whose direction remains the same is known as direct current. Direct current is defined by the constant flow of electrons from a region of high electron density to a region of low electron density. DC is used in many household appliances and applications that involve a battery.
The current electricity that is bidirectional and keeps changing the direction of the charge flow is known as alternating current. The bi-directionality is caused by a sinusoidally varying current and voltage that reverses directions, creating a periodic back-and-forth motion for the current. The electrical outlets at our homes and industries are supplied with alternating current.