Question

Given \( E(t) = 108t - 22 \), how is velocity derived from the electric field?

Hint:

To find the velocity from the electric field, integrate the electric field with respect to time, considering the charge and mass of the particle.

Answer 1

Step 1: Understanding the relationship between electric field and velocity.
The velocity \( v(t) \) of a charged particle in an electric field can be derived from the electric field \( E(t) \) by integrating it over time. The relationship is given by: \[ v(t) = \frac{q}{m} \int E(t) \, dt \] where \( q \) is the charge of the particle, \( m \) is the mass, and \( E(t) \) is the electric field as a function of time.
Step 2: Substituting the given electric field.
We are given \( E(t) = 108t - 22 \), so we substitute this into the equation: \[ v(t) = \frac{q}{m} \int (108t - 22) \, dt \] Step 3: Performing the integration.
Integrating \( 108t - 22 \) with respect to time: \[ \int (108t - 22) \, dt = \frac{108t^2}{2} - 22t + C \] Step 4: Final expression for velocity.
Thus, the velocity as a function of time is: \[ v(t) = \frac{q}{m} \left( \frac{108t^2}{2} - 22t + C \right) \] Step 5: Conclusion.
This is the expression for the velocity of the particle derived from the electric field.