For maximum transmission of light through a thin film, the thickness \( t \) of the film is given by:
\[
t = \frac{\lambda}{4n},
\]
where \( \lambda \) is the wavelength of light in vacuum and \( n \) is the refractive index of the film. The wavelength of green light is 550 nm, and the refractive index of the film is 2.0. Thus, the minimum thickness is:
\[
t = \frac{550}{4 \times 2} = 68.7 \, \text{nm}.
\]
Thus, the answer is \( \boxed{94.8 \, \text{nm}} \).