To understand the given assertion and reason, we need to evaluate both the behavior of light in an optically denser medium and the principles of Young's double slit experiment.
Assertion (A): When Young's double slit experiment is conducted in an optically denser medium than air, the consecutive fringes come closer.
Reason (R): The speed of light reduces in an optically denser medium than air while its frequency does not change.
Analysis:
1. The fringe separation (or fringe width, w) in Young's double slit experiment is given by the formula:
w = (λD) / d
Where λ is the wavelength of light, D is the distance between the slits and the screen, and d is the distance between the slits.
2. In an optically denser medium, the speed of light v is less than in air, while the frequency f of the light remains constant. Therefore, the wavelength in the medium λ' is given by:
λ' = v / f
3. The wavelength in the denser medium λ' is related to the wavelength in air λ by the refractive index n of the medium:
λ' = λ / n
4. Substituting λ' in the fringe width formula:
w' = (λ' D) / d = (λD) / (nd)
5. Since n > 1 in an optically denser medium, w' < w. This means the fringes are closer together in a denser medium compared to air.
Conclusion: Both the assertion (A) and the reason (R) are true. The density of the medium affects the speed of light, and hence the wavelength, which in turn affects the fringe spacing. The reduction in fringe spacing, as stated in the assertion, is correctly explained by the reason.
Correct Answer: Both (A) and (R) are true and (R) is the correct explanation of (A).
Concept:
In Young’s Double Slit Experiment (YDSE), the fringe width is given by:
$$ \beta = \dfrac{\lambda D}{d} $$ where
$\lambda$ = wavelength of light in the medium,
$D$ = distance between slits and screen,
$d$ = distance between the two slits.
In a denser medium, the wavelength decreases because:
$$ \lambda = \dfrac{v}{f} $$ and since the speed of light (v) decreases while frequency (f) remains constant, $\lambda$ becomes smaller.
Hence, the fringe width $\beta$ also decreases, which means the fringes come closer together.
Assertion (A): True — In an optically denser medium, consecutive fringes come closer.
Reason (R): True — Speed of light decreases, frequency remains the same.
Moreover, (R) correctly explains (A).
✅ Correct Answer: Option 1 — Both (A) and (R) are true and (R) is the correct explanation of (A)
Given below are two statements:
Statement (I):
are isomeric compounds.
Statement (II):
are functional group isomers.
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements: one is labelled as Assertion \(A\) and the other as Reason \(R\):
Assertion \(A\): A sound wave has higher speed in solids than in gases.
Reason \(R\): Gases have higher value of Bulk modulus than solids.
In the experiment for measurement of viscosity \( \eta \) of a given liquid with a ball having radius \( R \), consider following statements:
A. Graph between terminal velocity \( V \) and \( R \) will be a parabola.
B. The terminal velocities of different diameter balls are constant for a given liquid.
C. Measurement of terminal velocity is dependent on the temperature.
D. This experiment can be utilized to assess the density of a given liquid.
E. If balls are dropped with some initial speed, the value of \( \eta \) will change.