To understand the given assertion and reason, we need to evaluate both the behavior of light in an optically denser medium and the principles of Young's double slit experiment.
Assertion (A): When Young's double slit experiment is conducted in an optically denser medium than air, the consecutive fringes come closer.
Reason (R): The speed of light reduces in an optically denser medium than air while its frequency does not change.
Analysis:
1. The fringe separation (or fringe width, w) in Young's double slit experiment is given by the formula:
w = (λD) / d
Where λ is the wavelength of light, D is the distance between the slits and the screen, and d is the distance between the slits.
2. In an optically denser medium, the speed of light v is less than in air, while the frequency f of the light remains constant. Therefore, the wavelength in the medium λ' is given by:
λ' = v / f
3. The wavelength in the denser medium λ' is related to the wavelength in air λ by the refractive index n of the medium:
λ' = λ / n
4. Substituting λ' in the fringe width formula:
w' = (λ' D) / d = (λD) / (nd)
5. Since n > 1 in an optically denser medium, w' < w. This means the fringes are closer together in a denser medium compared to air.
Conclusion: Both the assertion (A) and the reason (R) are true. The density of the medium affects the speed of light, and hence the wavelength, which in turn affects the fringe spacing. The reduction in fringe spacing, as stated in the assertion, is correctly explained by the reason.
Correct Answer: Both (A) and (R) are true and (R) is the correct explanation of (A).
Let \( A = \{-3, -2, -1, 0, 1, 2, 3\} \). A relation \( R \) is defined such that \( xRy \) if \( y = \max(x, 1) \). The number of elements required to make it reflexive is \( l \), the number of elements required to make it symmetric is \( m \), and the number of elements in the relation \( R \) is \( n \). Then the value of \( l + m + n \) is equal to: