To understand the given assertion and reason, we need to evaluate both the behavior of light in an optically denser medium and the principles of Young's double slit experiment.
Assertion (A): When Young's double slit experiment is conducted in an optically denser medium than air, the consecutive fringes come closer.
Reason (R): The speed of light reduces in an optically denser medium than air while its frequency does not change.
Analysis:
1. The fringe separation (or fringe width, w) in Young's double slit experiment is given by the formula:
w = (λD) / d
Where λ is the wavelength of light, D is the distance between the slits and the screen, and d is the distance between the slits.
2. In an optically denser medium, the speed of light v is less than in air, while the frequency f of the light remains constant. Therefore, the wavelength in the medium λ' is given by:
λ' = v / f
3. The wavelength in the denser medium λ' is related to the wavelength in air λ by the refractive index n of the medium:
λ' = λ / n
4. Substituting λ' in the fringe width formula:
w' = (λ' D) / d = (λD) / (nd)
5. Since n > 1 in an optically denser medium, w' < w. This means the fringes are closer together in a denser medium compared to air.
Conclusion: Both the assertion (A) and the reason (R) are true. The density of the medium affects the speed of light, and hence the wavelength, which in turn affects the fringe spacing. The reduction in fringe spacing, as stated in the assertion, is correctly explained by the reason.
Correct Answer: Both (A) and (R) are true and (R) is the correct explanation of (A).
The motion of an airplane is represented by the velocity-time graph as shown below. The distance covered by the airplane in the first 30.5 seconds is km.
Which of the following statement is true with respect to H\(_2\)O, NH\(_3\) and CH\(_4\)?
(A) The central atoms of all the molecules are sp\(^3\) hybridized.
(B) The H–O–H, H–N–H and H–C–H angles in the above molecules are 104.5°, 107.5° and 109.5° respectively.
(C) The increasing order of dipole moment is CH\(_4\)<NH\(_3\)<H\(_2\)O.
(D) Both H\(_2\)O and NH\(_3\) are Lewis acids and CH\(_4\) is a Lewis base.
(E) A solution of NH\(_3\) in H\(_2\)O is basic. In this solution NH\(_3\) and H\(_2\)O act as Lowry-Bronsted acid and base respectively.
The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)?