Question

A solid cylinder is released from rest from the top of an inclined plane of inclination 30° and length 60 cm If the cylinder rolls without slipping, its speed upon reaching the bottom of the inclined plane is ________ $ms ^{-1}$(Given $g =10 \,ms ^{-2}$ )

Answer 1

Correct Answer: 2

$v=\sqrt{\frac{2gh}{1+\frac{k^2}{R^2}}}$

Where $h=60\sin 30^{\circ }=30cm$

$k^2=\frac{R^2}{2}$

$v=2m{s}^{-1}$
So, The correct answer is 2.