Question:

The apparent weight of a girl of mass 30 kg when she is in a lift moving vertically upwards with an acceleration of \( 2~\text{ms}^{-2} \) is
(Acceleration due to gravity = \( 10~\text{ms}^{-2} \))

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In a lift moving upward, apparent weight increases and is calculated using \( m(g + a) \). If the lift moves downward, use \( m(g - a) \).
Updated On: Jun 6, 2025
  • \( 60~\text{N} \)
  • \( 30~\text{N} \)
  • \( 240~\text{N} \)
  • \( 360~\text{N} \)
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The Correct Option is D

Solution and Explanation

Step 1: Recall the formula for apparent weight in a lift moving upward. \[ \text{Apparent weight} = m(g + a) \] Step 2: Substitute the values. \[ m = 30~\text{kg},
g = 10~\text{ms}^{-2},
a = 2~\text{ms}^{-2} \] \[ \text{Apparent weight} = 30(10 + 2) = 30 \times 12 = 360~\text{N} \] % Final Answer \[ \boxed{360~\text{N}} \]
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