In the given expression, the term \( At^2 \) has the dimension of velocity, which is \( [L T^{-1}] \). To maintain dimensional consistency, the term \( A \) must have the dimensions:
\[
A \sim \frac{[L T^{-1}]}{[T^2]} = [M L^2 T^{-3}]
\]
Similarly, the dimension of \( B \) and \( C \) can be derived to ensure the dimensions of the overall expression match those of velocity. The final result is \( [M L^2 T^{-3}] \).
Thus, the correct answer is \( [M L^2 T^{-3}] \).