Question

If the velocity at the maximum height of a projectile projected at an angle of \(45^\circ\) is \(20 \, \text{m/s}\), then the maximum height reached by the projectile is:

• A. 10 m
• B. 20 m
• C. 30 m
• D. 40 m

Hint:

At maximum height, the vertical velocity component is zero, and you can use the horizontal component to find the height.

Answer 1

The Correct Option is B

The velocity at the maximum height is the horizontal component of the velocity. Since the angle is \(45^\circ\), we know that the vertical component at the maximum height is zero. The formula for maximum height is: \[ H = \frac{v_y^2}{2g}, \] where \(v_y = 20 \, \text{m/s}\). Thus, \[ H = \frac{20^2}{2 \times 10} = 20 \, \text{m}. \]