A single current-carrying loop of wire carrying current I flows in the anticlockwise direction (seen from the +z direction) and lies in the xy plane. The plot of \(\hat{j}\) component of magnetic field (\(B_y\)) at a distance a (less than radius of the coil) and on the yz plane vs z coordinate looks like:
A single current-carrying loop of wire carrying current I flows in the anticlockwise direction (seen from the +z direction) and lies in the xy plane. The plot of \(\hat{j}\) component of magnetic field (\(B_y\)) at a distance a (less than radius of the coil) and on the yz plane vs z coordinate looks like:
Show Hint
For magnetic field due to current loops:
• Use the right-hand rule to determine the direction of the field.
• Symmetry plays a critical role in analyzing magnetic field variations.
The Correct Option is A
Solution and Explanation
- At z = 0 (plane of the loop), By = 0. - By is opposite in sign for +z and -z, as per the right-hand rule.
By = 0 in plane of coil By is opposite of each other in -z and +z positions.
Top Questions on Magnetic Field Due To A Current Element, Biot-Savart Law
- The angle between vector \( \vec{Q} \) and the resultant of \( (2\vec{Q} + 2\vec{P}) \) and \( (2\vec{Q} - 2\vec{P}) \) is:
- JEE Main - 2024
- Physics
- Magnetic Field Due To A Current Element, Biot-Savart Law
- Two parallel long current carrying wire separated by a distance $2r$ are shown in the figure. The ratio of magnetic field at $A$ to the magnetic field produced at $C$ is $\frac{x}{7}$. The value of $x$ is ___.
- JEE Main - 2024
- Physics
- Magnetic Field Due To A Current Element, Biot-Savart Law
- Three vectors \(\overrightarrow{OP}\), \(\overrightarrow{OQ}\), and \(\overrightarrow{OR}\) each of magnitude \(A\) are acting as shown in figure. The resultant of the three vectors is \(A \sqrt{x}\). The value of \(x\) is ______.
- JEE Main - 2024
- Physics
- Magnetic Field Due To A Current Element, Biot-Savart Law
- Two circular coils \(P\) and \(Q\) of \(100\) turns each have the same radius of \(\pi \, \text{cm}\). The currents in \(P\) and \(Q\) are \(1 \, \text{A}\) and \(2 \, \text{A}\) respectively. \(P\) and \(Q\) are placed with their planes mutually perpendicular with their centers coinciding. The resultant magnetic field induction at the center of the coils is \(\sqrt{x} \, \text{mT}\), where \(x =\) ______.
[Use \(\mu_0 = 4 \pi \times 10^{-7} \, \text{TmA}^{-1}\)]- JEE Main - 2024
- Physics
- Magnetic Field Due To A Current Element, Biot-Savart Law
A certain elastic conducting material is stretched into a circular loop. It is placed with its plane perpendicular to a uniform magnetic field B = 0.8 T. When released the radius of the loop starts shrinking at a constant rate of 2 cm/s. The induced emf in the loop at an instant when the radius of the loop is 10 cm will be _____ mV.
- JEE Main - 2023
- Physics
- Magnetic Field Due To A Current Element, Biot-Savart Law
Questions Asked in JEE Main exam
- Given below are two statements:
Statement (I): Corrosion is an electrochemical phenomenon in which pure metal acts as an anode and impure metal as a cathode.
Statement (II): The rate of corrosion is more in alkaline medium than in acidic medium.
In the light of the above statements, choose the correct answer from the options given below:- JEE Main - 2025
- Electrochemistry
- The number of solutions of the equation \[ \left( \frac{9}{x} - \frac{9}{\sqrt{x}} + 2 \right) \left( \frac{2}{x} - \frac{7}{\sqrt{x}} + 3 \right) = 0 \] is:
- JEE Main - 2025
- permutations and combinations
- Let \( (2, 3) \) be the largest open interval in which the function \( f(x) = 2 \log_e (x - 2) - x^2 + ax + 1 \) is strictly increasing, and \( (b, c) \) be the largest open interval, in which the function \( g(x) = (x - 1)^3 (x + 2 - a)^2 \) is strictly decreasing. Then \( 100(a + b - c) \) is equal to:
- JEE Main - 2025
- Quadratic Equations
- The sum of all local minimum values of the function \( f(x) \) as defined below is:
\[ f(x) = \left\{ \begin{array}{ll} 1 - 2x & \text{if } x < -1 \\ \frac{1}{3}(7 + 2|x|) & \text{if } -1 \leq x \leq 2 \\ \frac{11}{18} (x-4)(x-5) & \text{if } x > 2 \end{array} \right. \]
- JEE Main - 2025
- Functions
- Let \(\vec{a} = i + j + k\), \(\vec{b} = 2i + 2j + k\) and \(\vec{d} = \vec{a} \times \vec{b}\). If \(\vec{c}\) is a vector such that \(\vec{a} \cdot \vec{c} = |\vec{c}|\), \(\|\vec{c} - 2\vec{d}\| = 8\) and the angle between \(\vec{d}\) and \(\vec{c}\) is \(\frac{\pi}{4}\), then \(\left|10 - 3\vec{b} \cdot \vec{c} + |\vec{d}|\right|^2\) is equal to:
- JEE Main - 2025
- Vectors