Which of the following binary mixture does not show the behavior of minimum boiling azeotropes?
Show Hint
- \( \text{CS}_2 + \text{CH}_3\text{COCH}_3 \)
- \( \text{H}_2\text{O} + \text{CH}_3\text{COC}_2\text{H}_5 \)
- \( \text{C}_6\text{H}_5\text{OH} + \text{C}_6\text{H}_5\text{NH}_2 \)
- \( \text{CH}_3\text{OH} + \text{CHCl}_3 \)
The Correct Option is C
Solution and Explanation
Key Concept:
Minimum boiling azeotropes form when:
- Components show positive deviation from Raoult's law
- Molecular interactions between unlike molecules are weaker than between like molecules
- Typically occurs between molecules with different polarity or hydrogen bonding capacity
Analysis of Options:
- Option 1: CS2 + CH3COCH3
- Carbon disulfide (non-polar) + acetone (polar)
- Forms minimum boiling azeotrope (shows positive deviation)
- Option 2: H2O + CH3COC2H5
- Water (strong H-bonding) + methyl ethyl ketone (weak H-bonding)
- Forms minimum boiling azeotrope
- Option 3: C6H5OH + C6H5NH2
- Phenol + aniline (both can form strong intermolecular H-bonds)
- Shows negative deviation (forms maximum boiling azeotrope)
- Correct answer as it doesn't form minimum boiling azeotrope
- Option 4: CH3OH + CHCl3
- Methanol + chloroform (forms H-bonded complex)
- Shows positive deviation (minimum boiling azeotrope)
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