Question

A wire of length 0.5 m carrying a current of 3 A is placed in a magnetic field of 2 T perpendicular to the wire. What is the force on the wire?

• A. 1 N
• B. 3 N
• C. 0.75 N
• D. 6 N

Hint:

Use $F = BIL \sin\theta$ to find magnetic force. For perpendicular orientation, $\sin\theta = 1$.

Answer 1

The Correct Option is B

The magnetic force on a current-carrying conductor is given by: \[ F = BIL \sin\theta \] Where: \( B = 2 \, \text{T} \), \( I = 3 \, \text{A} \), \( L = 0.5 \, \text{m} \), and \( \theta = 90^\circ \) (perpendicular) \[ F = 2 \times 3 \times 0.5 \times \sin 90^\circ = 3 \, \text{N} \]