Question

A rectangular loop of length 2.5 m and width 2 m is placed at 60° to a magnetic field of 4 T. The loop is removed from the field in 10 sec. The average emf induced in the loop during this time is:

• A. -2V
• B. \(+2V\)
• C. \(+ 1V\)
• D. – 1V

Answer 1

The Correct Option is C

The average emf induced in the loop is given by:

\[ \text{Average emf} = -\frac{\Delta \Phi}{\Delta t} = -\frac{0 - (4 \times (2.5 \times 2) \cos 60^\circ)}{10} \]

Calculating the flux change:

\[ \Delta \Phi = 4 \times (2.5 \times 2) \times \frac{1}{2} = 10 \text{ Wb} \]

Then,

\[ \text{Average emf} = -\frac{-10}{10} = +1 \text{ V} \]