Question

A coil of an AC generator, having 100 turns and area 0.1 m² each, rotates at half a rotation per second in a magnetic field of 0.02 T. The maximum emf generated in the coil is:

• A. 0.31 V
• B. 0.20 V
• C. 0.63 V
• D. 0.10 V

Hint:

The maximum induced emf in a rotating coil depends on the number of turns, the area of the coil, the strength of the magnetic field, and the angular velocity of the coil.

Answer 1

The Correct Option is A

Step 1: The formula. The maximum emf induced in a coil rotating in a magnetic field is given by: \[ \text{emf}_{\text{max}} = N A B \omega \] Where \( N \) is the number of turns, \( A \) is the area of the coil, \( B \) is the magnetic field strength, and \( \omega \) is the angular velocity.

Step 2: Applying the values. Substituting the values \( N = 100 \), \( A = 0.1 \, \text{m}^2 \), \( B = 0.02 \, \text{T} \), and \( \omega = 2\pi \times 0.5 \), the maximum emf is \( 0.31 \, \text{V} \), corresponding to option .