Question:

A coil has 100 turns, each of area \( 0.05 \, \text{m}^2 \) and total resistance \( 1.5 \, \Omega \). It is inserted at an instant in a magnetic field of \( 90 \, \text{mT} \), with its axis parallel to the field. The charge induced in the coil at that instant is:

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Remember that the induced charge is related to the change in magnetic flux through the coil, and depends on the number of turns, the area, and the magnetic field strength.
  • \( 3.0 \, \text{mC} \)
  • \( 0.30 \, \text{C} \)
  • \( 0.45 \, \text{C} \)
  • \( 1.5 \, \text{C} \)
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The Correct Option is B

Solution and Explanation

The induced charge in the coil is given by Faraday's law: \[ Q = \frac{N \cdot A \cdot B}{R} \cdot \Delta t \] where: - \( N = 100 \) is the number of turns, - \( A = 0.05 \, \text{m}^2 \) is the area of each turn, - \( B = 90 \, \text{mT} = 0.09 \, \text{T} \) is the magnetic field strength, - \( R = 1.5 \, \Omega \) is the total resistance of the coil. Substitute these values into the formula: \[ Q = \frac{100 \cdot 0.05 \cdot 0.09}{1.5} = 0.30 \, \text{C} \] Thus, the correct answer is \( 0.30 \, \text{C} \). 

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