The induced charge in the coil is given by Faraday's law: \[ Q = \frac{N \cdot A \cdot B}{R} \cdot \Delta t \] where:
\( N = 100 \) is the number of turns,
\( A = 0.05 \, \text{m}^2 \) is the area of each turn,
\( B = 90 \, \text{mT} = 0.09 \, \text{T} \) is the magnetic field strength,
\( R = 1.5 \, \Omega \) is the total resistance of the coil.
Substitute these values into the formula: \[ Q = \frac{100 \cdot 0.05 \cdot 0.09}{1.5} = 0.30 \, \text{C} \] Thus, the correct answer is \( 0.30 \, \text{C} \).
Assertion : In an ideal step-down transformer, the electrical energy is not lost.
Reason (R): In a step-down transformer, voltage decreases but the current increases.
Find the Derivative \( \frac{dy}{dx} \)
Given:\[ y = \cos(x^2) + \cos(2x) + \cos^2(x^2) + \cos(x^x) \]