Question:

A parallel beam of monochromatic light of wavelength 5000 •Å is incident normally on a single narrow slit of width 0.001 mm. The light is focused by convex lens on screen, placed on its focal plane. The first minima will be formed for the angle of diffraction of ________ (degree).

Updated On: Nov 16, 2024
Hide Solution
collegedunia
Verified By Collegedunia

Correct Answer: 30

Solution and Explanation

For the first minima in a single-slit diffraction pattern:

\(a \sin \theta = \lambda\)

Given:
- \( a = 0.001 \, \text{mm} = 1 \times 10^{-6} \, \text{m} \),
- \( \lambda = 5000 \, \text{Å} = 5000 \times 10^{-10} \, \text{m} \).

Substituting:

\(\sin \theta = \frac{\lambda}{a} = \frac{5000 \times 10^{-10}}{1 \times 10^{-6}} = 0.5\)

\(\theta = \sin^{-1}(0.5) = 30^\circ\)
The Correct answer is: 30

Was this answer helpful?
0
0

Top Questions on Optics

View More Questions

Questions Asked in JEE Main exam

View More Questions