Question

A p-n junction diode is reverse biased with a voltage of 8 V. If the resistance of the diode is \( 4 \times 10^7 \, \Omega \), then the reverse saturation current is

• A. \( 32 \, \mu A \)
• B. \( 2 \, \mu A \)
• C. \( 0.2 \, \mu A \)
• D. \( 0.5 \, \mu A \)

Hint:

For calculating current in resistive components, use Ohm’s law. Make sure to convert units correctly when working with small values such as microamperes.

Answer 1

The Correct Option is C

The reverse saturation current in a diode can be calculated using Ohm's Law: \[ I = \frac{V}{R} \] where \( I \) is the current, \( V \) is the applied reverse bias voltage, and \( R \) is the resistance of the diode. Given: \[ V = 8 \, \text{V}, \quad R = 4 \times 10^7 \, \Omega \] Substitute the values into the equation: \[ I = \frac{8}{4 \times 10^7} = 0.2 \times 10^{-6} \, \text{A} = 0.2 \, \mu A \] Thus, the reverse saturation current is \( 0.2 \, \mu A \). Therefore, the correct answer is \( \boxed{0.2 \, \mu A} \).