In Young’s double slit experiment, the wavelengths of red and blue lights used are \(7.5 \times 10^{-5}\) cm and \(5 \times 10^{-5}\) cm respectively. If the \(n^{th}\) bright fringe of red color coincides with \((n+1)^{th}\) bright fringe of blue colour, then the value of \( n \) is
Show Hint
Match fringe positions using wavelength and fringe number relationships in double slit experiment.
Step 1: Fringe position formula
The position of bright fringes in double slit experiment is proportional to wavelength \( \lambda \) and fringe number \( n \):
\[
y \propto n \lambda
\]
Step 2: Condition for coincidence
\[
n \lambda_{red} = (n+1) \lambda_{blue}
\]
Substitute values:
\[
n \times 7.5 \times 10^{-5} = (n + 1) \times 5 \times 10^{-5}
\]
Step 3: Solve for \( n \)
\[
7.5 n = 5 n + 5 \implies 2.5 n = 5 \implies n = 2
\]
Step 4: Conclusion
The value of \( n \) is 2.