\(\frac{I_0}{2}\)
\(\frac{I_0}{4}\)
\(\frac{I_0}{8}\)
Relation between intensities is \(I_R=\big(\frac{I_0}{2}\big)cos^2 (45^\circ)\)
\(=\frac{I_0}{2} \times \frac{1}{2}=\frac{I_0}{4}\)
Therefore, The correct answer is (C) : \(\frac{I_0}{4}\)
A point particle of charge \( Q \) is located at \( P \) along the axis of an electric dipole 1 at a distance \( r \) as shown in the figure. The point \( P \) is also on the equatorial plane of a second electric dipole 2 at a distance \( r \). The dipoles are made of opposite charge \( q \) separated by a distance \( 2a \). For the charge particle at \( P \) not to experience any net force, which of the following correctly describes the situation?

