Given:
- Mass of organic compound = 0.5 g
- Mass of CO\(_2\) = 1.46 g
- Mass of H\(_2\)O = 0.9 g
To find the percentage composition of carbon, we first need to find the amount of carbon in CO\(_2\).
- Moles of CO\(_2\):
\[
\text{Moles of CO}_2 = \frac{1.46}{44} = 0.03318 \, \text{mol}
\]
Each mole of CO\(_2\) contains 1 mole of carbon, so:
\[
\text{Moles of carbon} = 0.03318 \, \text{mol}
\]
Mass of carbon = \( 0.03318 \, \text{mol} \times 12 = 0.398 \, \text{g} \).
Now, the percentage composition of carbon is:
\[
\text{Percentage of carbon} = \frac{0.398}{0.5} \times 100 = 79.6\%
\]