A proton (\( p \)) and an electron (\( e \)) will have the same de-Broglie wavelength when the ratio of their momenta is (Assume \( m_p = 1849 m_e \)):
An object moves with speed \( v_1 \), \( v_2 \), and \( v_3 \) along a line segment \( AB \), \( BC \), and \( CD \) respectively as shown in the figure. Where \( AB = BC \) and \( AD = 3 AB \), then the average speed of the object will be:
The energy levels of an atom are shown in the figure. Which one of these transitions will result in the emission of a photon of wavelength 124.1 nm? Given \( h = 6.62 \times 10^{-34} \) Js.
A thermodynamic system is taken through a cyclic process as shown in the PV diagram. The total work done in the process is: