A disc is rolling without slipping on a surface. The radius of the disc is \( R \). At \( t = 0 \), the topmost point on the disc is \( A \) as shown in the figure. When the disc completes half of its rotation, the displacement of point \( A \) from its initial position is:
An object moves with speed \( v_1 \), \( v_2 \), and \( v_3 \) along a line segment \( AB \), \( BC \), and \( CD \) respectively as shown in the figure. Where \( AB = BC \) and \( AD = 3 AB \), then the average speed of the object will be:
At a certain depth "$d$" below surface of earth, value of acceleration due to gravity becomes four times that of its value at a height $3 R$ above earth surface Where $R$ is Radius of earth (Take $R =6400\, km$ ) The depth $d$ is equal to
A square frame of side \( 10 \) cm and a long straight wire carrying current \( 1A \) are in the plane of the paper. Starting from close to the wire, the frame moves towards the right with a constant speed of \( 10 \) m/s (see figure). The induced EMF at the time the left arm of the frame is at \( x = 10 \) cm from the wire is: