Step 1: Understanding the Concept of Center of Mass
- The spheres are made of the same material, meaning their masses are proportional to their volumes. - The mass of a sphere is given by: \[ m = \rho \times \frac{4}{3} \pi r^3 \] where \( \rho \) is the density of the material.
Step 2: Center of Mass Formula for Two Particles
- The center of mass for two objects is given by: \[ X_{\text{cm}} = \frac{m_1 x_1 + m_2 x_2}{m_1 + m_2} \]
Step 3: Substituting Masses of Spheres
Since mass is proportional to \( r^3 \): \[ X_{\text{cm}} = \frac{r_2^3 \times (r_1 + r_2)}{r_1^3 + r_2^3} \]
Step 4: Conclusion
Since the distance of the center of mass from the point of contact is \( \frac{r_2^3 (r_1 + r_2)}{r_1^3 + r_2^3} \), Option (4) is correct.
Observe the following data given in the table. (\(K_H\) = Henry's law constant)
| Gas | CO₂ | Ar | HCHO | CH₄ |
|---|---|---|---|---|
| \(K_H\) (k bar at 298 K) | 1.67 | 40.3 | \(1.83 \times 10^{-5}\) | 0.413 |
The correct order of their solubility in water is
For a first order decomposition of a certain reaction, rate constant is given by the equation
\(\log k(s⁻¹) = 7.14 - \frac{1 \times 10^4 K}{T}\). The activation energy of the reaction (in kJ mol⁻¹) is (\(R = 8.3 J K⁻¹ mol⁻¹\))
Note: The provided value for R is 8.3. We will use the more precise value R=8.314 J K⁻¹ mol⁻¹ for accuracy, as is standard.