Step 1: For the reflected light to be completely polarized, the angle of incidence must be equal to the Brewster angle, \( \theta_B \), which is given by: \[ \tan \theta_B = n \] where \( n \) is the refractive index of the medium.
Step 2: Given that the angle of incidence is \( 60^\circ \), we can equate this to the Brewster angle: \[ \tan 60^\circ = n \] \[ n = \sqrt{3} \]
A beam of light traveling horizontally consists of an unpolarized component with intensity \( I_0 \) and a polarized component with intensity \( I_p \). The plane of polarization is oriented at an angle \( \theta \) with respect to the vertical. The figure shows the total intensity \( I_{\text{total}} \) after the light passes through a polarizer as a function of the angle \( \alpha \), that the axis of the polarizer makes with respect to the vertical. Identify the correct statement(s). 
A beam of unpolarized light of intensity \(I_0\) falls on a system of four identical linear polarizers placed in a line as shown in the figure. The transmission axes of any two successive polarizers make an angle of \(30^\circ\) with each other. If the transmitted light has intensity \(I\), the ratio \(\dfrac{I}{I_0}\) is: 

