Step 1: The terminal velocity \( v_t \) of a spherical object falling through a fluid is given by: \[ v_t \propto r^2 \] where \( r \) is the radius of the sphere.
Step 2: Given the ratio of the radii \( r_1/r_2 = 4/5 \), the ratio of the terminal velocities is: \[ \frac{v_{t1}}{v_{t2}} = \left( \frac{r_1}{r_2} \right)^2 = \left( \frac{4}{5} \right)^2 = \frac{16}{25} \]
Step 3: Thus, the ratio of the terminal velocities is \( 16:25 \).
A cube of side 10 cm is suspended from one end of a fine string of length 27 cm, and a mass of 200 grams is connected to the other end of the string. When the cube is half immersed in water, the system remains in balance. Find the density of the cube.

