Step 1: The drift velocity \( v_d \) of electrons is related to the electric field \( E \) and the relaxation time \( \tau \) by the equation: \[ v_d = \mu E \] where \( \mu \) is the mobility of electrons.
Step 2: The drift velocity is proportional to the product of the relaxation time and the applied electric field. Doubling the relaxation time and tripling the electric field results in: \[ v_d' = \frac{2\tau \times 3E}{\tau E} = 6 \times v_d \]
Step 3: Thus, the drift velocity decreases by a factor of 6.
A metallic ring is uniformly charged as shown in the figure. AC and BD are two mutually perpendicular diameters. Electric field due to arc AB to O is ‘E’ magnitude. What would be the magnitude of electric field at ‘O’ due to arc ABC? 
In a messenger RNA molecule, untranslated regions (UTRs) are present at:
I. 5' end before start codon
II. 3' end after stop codon
III. 3' end before stop codon
IV. 5' end after start codon

