The combustion of benzene $ (l)$ gives $CO_2(g)$ and $H_2O(l)$ . Given that heat of combustion of benzene at constant volume is $-3263.9 \, kJ \, mol^{-1}$ at $25^{\circ} C$ ; heat of combustion (in $ kJ \, mol^{-1}$ ) of benzene at constant pressure will be -$ (R = 8.314 \, JK^{-1} \, mol^{-1}) $