In a reaction,
reagents ' X ' and ' Y ' respectively are :
Recognize the functional groups involved and the type of reaction taking place. Fischer esterification is a common method for preparing esters from carboxylic acids or phenolic OH groups.
\(CH _3 OH / H ^{+}, \Delta and CH _3 OH / H ^{+}, \Delta\)
\(\left( CH _3 CO \right)_2 O / H ^{+}and CH _3 OH / H ^{+}, \Delta\)
\(\left( CH _3 CO \right)_2 O / H ^{+} and \left( CH _3 CO \right)_2 O / H ^{+}\)
\(CH _3 OH / H ^{+}, \Delta and \left( CH _3 CO \right)_2 O / H ^{+}\)
Step 1: Analyze the Reaction from B to C (Reagent ‘X’)
The transformation from B to C involves the esterification of the phenolic \(-\text{OH}\) group.
This can be achieved using acetic anhydride (\((\text{CH}_3\text{CO})_2\text{O}\)) in the presence of an acid catalyst (\(\text{H}^+\)). This reaction is known as Fischer esterification.
Step 2: Analyze the Reaction from B to A (Reagent ‘Y’)
The transformation from B to A involves the esterification of the carboxylic acid group (\(-\text{COOH}\)) with methanol (\(\text{CH}_3\text{OH}\)) in the presence of an acid catalyst (\(\text{H}^+\)) and heat (\(\Delta\)). This is also a Fischer esterification.
Conclusion
The reagents X and Y are \((\text{CH}_3\text{CO})_2\text{O}/\text{H}^+\) and \(\text{CH}_3\text{OH}/\text{H}^+, \Delta\),.
A bob of mass \(m\) is suspended at a point \(O\) by a light string of length \(l\) and left to perform vertical motion (circular) as shown in the figure. Initially, by applying horizontal velocity \(v_0\) at the point ‘A’, the string becomes slack when the bob reaches at the point ‘D’. The ratio of the kinetic energy of the bob at the points B and C is:
Read Also: Aldehydes, Ketones, and Carboxylic Acids
Read More: Chemistry Named Reactions