In a reaction,
reagents ' X ' and ' Y ' respectively are :
Recognize the functional groups involved and the type of reaction taking place. Fischer esterification is a common method for preparing esters from carboxylic acids or phenolic OH groups.
\(CH _3 OH / H ^{+}, \Delta and CH _3 OH / H ^{+}, \Delta\)
\(\left( CH _3 CO \right)_2 O / H ^{+}and CH _3 OH / H ^{+}, \Delta\)
\(\left( CH _3 CO \right)_2 O / H ^{+} and \left( CH _3 CO \right)_2 O / H ^{+}\)
\(CH _3 OH / H ^{+}, \Delta and \left( CH _3 CO \right)_2 O / H ^{+}\)
Step 1: Analyze the Reaction from B to C (Reagent ‘X’)
The transformation from B to C involves the esterification of the phenolic \(-\text{OH}\) group.
This can be achieved using acetic anhydride (\((\text{CH}_3\text{CO})_2\text{O}\)) in the presence of an acid catalyst (\(\text{H}^+\)). This reaction is known as Fischer esterification.
Step 2: Analyze the Reaction from B to A (Reagent ‘Y’)
The transformation from B to A involves the esterification of the carboxylic acid group (\(-\text{COOH}\)) with methanol (\(\text{CH}_3\text{OH}\)) in the presence of an acid catalyst (\(\text{H}^+\)) and heat (\(\Delta\)). This is also a Fischer esterification.
Conclusion
The reagents X and Y are \((\text{CH}_3\text{CO})_2\text{O}/\text{H}^+\) and \(\text{CH}_3\text{OH}/\text{H}^+, \Delta\),.
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is:
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