A mixture of $1.57\,mol$ of $N_2$, $1.92\, mol$ of $H_2$ and $8.13\,mol$ of $NH_3$ is introduced into a $20\,L$ reaction vessel at $500\, K$. At this temperature, the equilibrium constant, $K_c$ for the reaction, $ {N_{2(g)} + 3H_{2(g)} <=> 2NH_{3(g)}}$ is $1.7 \times 10^2$. What is the direction of the net reaction?