Question:
In the presence of peroxide, $HCl$ and $HI$ do not give anti-Markownikoff' s addition to alkenes because :
In the presence of peroxide, $HCl$ and $HI$ do not give anti-Markownikoff' s addition to alkenes because :
Updated On: Oct 10, 2024
- One of the steps is endothermic in HCl and HI
- Both HCl and HI are strong acids
- HCl is oxidizing and the HI is reducing
- All the steps are exothermic in HCl and HI
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Anti-Markownikoff addition is possible only in case of $HBr$ and not in $HCl$ and $HI$. In $HBr$ both the chain initiation and propagation steps are exothermic, while in $HCl$, first step is exothermic, and second step is endothermic and in $HI$, no step is exothermic. Hence $HCl$ and $HI$ do not undergo anti-Markownikoff?s addition.
Was this answer helpful?
0
0
Top Questions on Hydrocarbons
Complete the following reactions by writing the structure of the main products:
- CBSE CLASS XII - 2025
- Chemistry
- Hydrocarbons
- Complete the following reactions by writing the structural formulae of ‘A’ and ‘B’:
(i) CH$_3$CH=CH$_2$ + HBr $\xrightarrow{\text{Peroxide}}$ ‘A’ $\xrightarrow{KOH}$ ‘B’
(ii) CH$_3$CH$_2$CHCl + alc. KOH $\xrightarrow{\Delta}$ ‘A’ $\xrightarrow{\text{H}_2\text{O}}$ ‘B’ (Main product)- CBSE CLASS XII - 2025
- Chemistry
- Hydrocarbons
- A halide with formula C6H13Br gave two isomeric alkenes A and B on dehydrobromination. On ozonolysis of mixture of A and B the following compounds were obtained: CH3COCH3, CH3CHO, CH3CH2CHO and (CH3)2CHCHO. The halide is:
- AP EAPCET - 2025
- Chemistry
- Hydrocarbons
- Which of the following is an alkene?
- BITSAT - 2025
- Chemistry
- Hydrocarbons
- Which of the following is a mild base?
- TS POLYCET - 2025
- Chemistry
- Hydrocarbons
View More Questions
Questions Asked in JEE Main exam
- If \(a = 1 + \sum_{r=1}^{6} (-3)^{r-1} \binom{12}{2r-1}\), then the distance of the point \((12, \sqrt{3})\) from the line \(\alpha x - \sqrt{3}y + 1 = 0\) is:
- JEE Main - 2025
- Coordinate Geometry
- Let \( \alpha, \beta, \gamma \) and \( \delta \) be the coefficients of \( x^7, x^5, x^3, x \) respectively in the expansion of \( (x + \sqrt{x^3 - 1})^5 + (x - \sqrt{x^3 - 1})^5, \, x > 1 \). If \( \alpha u + \beta v = 18 \), \( \gamma u + \delta v = 20 \), then \( u + v \) equals:
- JEE Main - 2025
- binomial expansion formula
- Let \[ \int x^3 \sin x \, dx = g(x) + C, \quad \text{where \( C \) is the constant of integration.} \] If \[ g\left( \frac{\pi}{2} \right) + g\left( \frac{\pi}{2} \right) = \alpha \pi^3 + \beta \pi^2 + \gamma, \quad \alpha, \beta, \gamma \in {Z}, \] then \[ \alpha + \beta - \gamma \text{ equals:} \]
- JEE Main - 2025
- Integration by Parts
- The center of mass of a thin rectangular plate (fig - x) with sides of length \( a \) and \( b \), whose mass per unit area (\( \sigma \)) varies as \( \sigma = \sigma_0 \frac{x}{ab} \) (where \( \sigma_0 \) is a constant), would be
- JEE Main - 2025
- System of Particles & Rotational Motion
Electrolysis of 600 mL aqueous solution of NaCl for 5 min changes the pH of the solution to 12. The current in Amperes used for the given electrolysis is ….. (Nearest integer).
- JEE Main - 2025
- Electrolysis
View More Questions
Concepts Used:
Hydrocarbons
Hydrocarbons can be described as organic compounds that consists only hydrogen and carbon atoms. These compounds are of different types and thereby have distinct natures. Hydrocarbons are colorless gases and are known for discharging faint odours. These have been categorized under four major classes named as alkynes, alkanes, alkenes, and aromatic hydrocarbons.
Types of Hydrocarbons
- Saturated hydrocarbons - Saturated hydrocarbons are those compounds where there is a single bond exists between carbon atoms and are saturated with atoms of hydrogen.
- Unsaturated hydrocarbons - Hydrocarbons comprises of at least one double or triple bond between carbon atoms are known as unsaturated hydrocarbons.
- Aliphatic hydrocarbons - The term denotes the hydrocarbons formed as an outcome of the chemical degradation of fats. Aliphatic hydrocarbons are basically chemical compounds.
- Aromatic hydrocarbons - They are distinguished because of the presence of benzene rings in them. They give away distinct types of aroma. These hydrocarbons comprises of only hydrogen and carbon atoms.