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List of top Mathematics Questions asked in BITSAT
The locus of
$z$
satisfying the inequality
$\frac{z + 2i}{2z + i} < 1$
, where
$z = x + iy$
, is
BITSAT - 2009
BITSAT
Mathematics
Complex numbers
The period of
$\sin^4 \, x + \cos^4 \, x$
is
BITSAT - 2009
BITSAT
Mathematics
Inverse Trigonometric Functions
For
$| x | < 1$
, the constant term in the expansion of
$\frac{1}{x -1^2 x - 2}$
is
BITSAT - 2009
BITSAT
Mathematics
general and middle terms
$\frac{\cos \, x}{\cos \, x -2y} = \lambda \, \Rightarrow \, \tan \, x - y$
is equal to
BITSAT - 2009
BITSAT
Mathematics
Trigonometric Identities
The locus of centre of a circle which passes through the origin and cuts off a length of $4$ unit from the line $x = 3$ is
BITSAT - 2009
BITSAT
Mathematics
circle
$\cos \, A \, \cos \, 2A \, \cos \, 4A ... \cos \, 2^{n -1} A$
equals
BITSAT - 2009
BITSAT
Mathematics
Trigonometric Equations
The image of the point $(3, 2, 1)$ in the plane $2x-y+3z = 7$ is
BITSAT - 2009
BITSAT
Mathematics
coordinates of a point in space
If
$x, y, z$
are all positive and are the
$p^{th}, q^{th}$
and
$r^{th}$
terms of a geometric progression respectively, then the value of the determinant $\begin{vmatrix} \log x & p & 1 \\ \log y & q & 1 \\ \log z & r & 1 \end{vmatrix} = 0 $ equals
BITSAT - 2009
BITSAT
Mathematics
Properties of Determinants
$x \in R : \frac{2x -1}{x^3 + 4x^2 + 3x} \in R$ Equals
BITSAT - 2009
BITSAT
Mathematics
Relations and functions
If
$m_1, m_2, m_3$
and
$m_4$
are respectively the magnitudes of the vectors
$a_1 = 2i - j + k, a_2 = 3i - 4j - 4 k $
$a_3 = i + j - k$
and
$a_4 = - i + 3j + k , $
then the correct order of
$m_1, m_2, m_3 $
and
$m_4$
is
BITSAT - 2009
BITSAT
Mathematics
Vectors
If $A$ and $B$ are independent events of a random experiment such that $P(A \cap B) = \frac{1}{6} $ and $P(A \cap B) = \frac{1}{3}$, then $P(A)$ is equal to (Here, $E$ is the complement of the event $E$)
BITSAT - 2008
BITSAT
Mathematics
Independent Events
If the lines $2x - 3y = 5$ and $3x - 4y = 7$ are two diameters of a circle of radius $7$, then the equation of the circle is
BITSAT - 2008
BITSAT
Mathematics
circle
The inverse of the point $(1, 2)$ with respect to the circle $x^2 + y^2 - 4x - 6y + 9 = 0$, is
BITSAT - 2008
BITSAT
Mathematics
circle
The radius of the circle with the polar equation $r^2 - 8r( \sqrt{3} \, \cos \, \theta + \sin \, \theta) + 15 = 0$ is
BITSAT - 2008
BITSAT
Mathematics
circle
The distance between the foci of the hyperbola $x^2 - 3y^2 - 4x - 6y -11 = 0$ is
BITSAT - 2008
BITSAT
Mathematics
Hyperbola
If $2x + 3y + 12 = 0$ and $x - y + 4 \lambda = 0$ are conjugate with respect to the parabola $y^2 = 8x$, then $\lambda$ is equal to
BITSAT - 2008
BITSAT
Mathematics
Parabola
If $f: R \rightarrow R$ is defined by $f(x)=[x-3]+|x-4|$ for $x \in R$, then $\displaystyle\lim _{x \rightarrow 3} f(x)$ is equal to
BITSAT - 2008
BITSAT
Mathematics
Limits
If $f : R \rightarrow R$ is defined by $f(x) = \begin{cases} \frac{\cos \ 3x - \cos \ x}{x^2} &, \text{for } x \neq 0 \\ \lambda &, \text{for } x = \end{cases}$ and if $f$ is continuous at $x = 0,$ then $\lambda$ is equal to
BITSAT - 2008
BITSAT
Mathematics
Limits
If $f(2) = 4$ and $f'(2) = 1$, then $\displaystyle\lim_{x \to 2} \frac{xf (2) - 2 f (x) }{x -2}$ is equal to
BITSAT - 2008
BITSAT
Mathematics
Limits
In $\triangle A B C$ the mid points of the sides $A B, B C$ and $C A$ are respectively $(1,0,0),(0$, $m , 0)$ and $(0,0, n )$. Then, $\frac{A B^{2}+B C^{2}+C A^{2}}{l^{2}+m^{2}+n^{2}}$ is equal to
BITSAT - 2008
BITSAT
Mathematics
Three Dimensional Geometry
A pair of perpendicular straight lines passes through the origin and also through the point of intersection of the curve $x^2 + y^2 = 4$ with $x + y = a$. The set containing the value of '$a$' is
BITSAT - 2008
BITSAT
Mathematics
Horizontal and vertical lines
The solution of the differential equation $\frac{dy}{dx} = \frac{xy + y}{xy + x}$ is
BITSAT - 2008
BITSAT
Mathematics
Differential equations
$(x -1) (x^2 - 5x + 7) < (x -,1),$
then
$x$
belongs to
BITSAT - 2007
BITSAT
Mathematics
Relations and functions
The probability that the same number appear on throwing three dice simultaneously, is
BITSAT - 2007
BITSAT
Mathematics
Conditional Probability
Let A be an orthogonal non-singular matrix of order
$n$
, then the determinant of matrix
$AI _{ n }$
ie,
$\left| A - I _{ n }\right|$
is equal to
BITSAT - 2007
BITSAT
Mathematics
Determinants
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