The given reaction is the coupling of an alkyl halide (C\(_6\)H\(_5\)Cl) with sodium (Na) in dry ether, resulting in the formation of a biphenyl (C\(_6\)H\(_5\)-C\(_6\)H\(_5\)).
Step 1: Wurtz Fittig reaction overview.
The Wurtz Fittig reaction involves the coupling of an alkyl halide with an aryl halide using sodium metal in dry ether to form a biphenyl (or similar products). This is a variation of the Wurtz reaction, where the Wurtz reaction involves the coupling of two alkyl halides, and the Fittig variation involves one aryl and one alkyl halide.
Step 2: Evaluate the options.
- Option 1: Sandmeyer’s reaction: This reaction is used for the synthesis of aryl halides from diazonium salts, not for the coupling of alkyl and aryl halides.
- Option 2: Wurtz reaction: The Wurtz reaction is a coupling of two alkyl halides, not an alkyl-aryl coupling.
- Option 3: Wurtz Fittig reaction: This is the correct answer. The reaction is the coupling of an alkyl halide with an aryl halide to form biphenyl.
- Option 4: Kolbe reaction: The Kolbe reaction is used to form carboxylates from alkyl or aryl halides in the presence of sodium, which is unrelated to this reaction.
Step 3: Conclusion.
The reaction is an example of the Wurtz Fittig reaction, where an alkyl halide reacts with an aryl halide in the presence of sodium to form a biphenyl compound.
Final Answer:
\[
\boxed{\text{The correct answer is Wurtz Fittig reaction.}}
\]