Step 1: Condition on Divisibility
The number must be divisible by all prime numbers less than 15.
Primes less than 15 are:
\[
2, \; 3, \; 5, \; 7, \; 11, \; 13
\]
Their least common multiple (LCM) is:
\[
\text{LCM} = 2 \times 3 \times 5 \times 7 \times 11 \times 13 = 30030
\]
Step 2: Six-Digit Number Requirement
So the six-digit number must be a multiple of 30030.
Step 3: Positional Restrictions
- Second last digit = 2
- Third last digit = 4
So the number must look like:
\[
\_\_\_\;4\;2\_\;
\]
(Example: \(\;abc42d\;\))
Step 4: Checking Multiples of 30030
Now, multiples of 30030 near the six-digit range must be checked until one fits the pattern **_42_** at the end.
Indeed, one such multiple is 504210.
Step 5: Identify First Digit
The number 504210 fits all conditions:
- Six digits ✔️
- Divisible by 30030 ✔️
- Second last digit = 2 ✔️
- Third last digit = 4 ✔️
Thus, the **first digit = 5**.
Final Answer:
\[
\boxed{\text{5}}
\]
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is:
A | B | C | D | Average |
---|---|---|---|---|
3 | 4 | 4 | ? | 4 |
3 | ? | 5 | ? | 4 |
? | 3 | 3 | ? | 4 |
? | ? | ? | ? | 4.25 |
4 | 4 | 4 | 4.25 |