Question

Which interchange in sign and number would make the equation correct? \[ (96 + 128) + 64 = 2 \]

• A. + and ÷, 64 and 96
• B. + and ÷, 64 and 128
• C. + and ÷, 96 and 128
• D. + and ÷, 96 and 128

Hint:

When dealing with equations involving sign changes, systematically test each option to verify if the resulting equation is valid.

Answer 1

The Correct Option is B

The equation is: \[ (96 + 128) + 64 = 2 \] First, simplify the equation: \[ 224 + 64 = 2 \quad \text{(which is not correct)}. \] Now, interchange "+" with "÷" and swap 64 and 128. The equation becomes: \[ (96 \div 128) + 64 = 2 \] Simplifying the left-hand side: \[ 0.75 + 64 = 2 \quad \text{(which is correct)}. \] Thus, option (2) makes the equation correct.