Question:

In an 8-week course, the teacher conducts a test every week, and the scores are in the range of 1–4. There are only two students enrolled in the course, RR and SS. The following conditions are given:
  1. RR and SS scored the same on the first test.
  2. From the second test onwards, RR consistently scored the same (a non-zero score).
  3. The total of the first three test scores of RR equals the total of the first two test scores of SS.
  4. From the fifth test onwards, SS scored the same as RR.
  5. The scores of SS from the first two tests and all the remaining tests follow a geometric progression.

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In problems with geometric progressions, identify the common ratio r and use boundary conditions to limit possible values. Check all constraints step-by-step for consistency.
Updated On: Jan 15, 2025
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Solution and Explanation

Let the scores of RR and SS for the tests be as follows:

  • Scores of RR: R1,R2,R3,R4,R5,R6,R7,R8R_1, R_2, R_3, R_4, R_5, R_6, R_7, R_8
  • Scores of SS: S1,S2,S3,S4,S5,S6,S7,S8S_1, S_2, S_3, S_4, S_5, S_6, S_7, S_8

Step 1: Analyze the conditions

  1. From condition 1: R1=S1R_1 = S_1
  2. From condition 2: R2=R3=R4=R5=R6=R7=R8=kR_2 = R_3 = R_4 = R_5 = R_6 = R_7 = R_8 = k, where kk is a constant score.
  3. From condition 3: R1+R2+R3=S1+S2R_1 + R_2 + R_3 = S_1 + S_2
  4. From condition 4: S5=S6=S7=S8=kS_5 = S_6 = S_7 = S_8 = k
  5. From condition 5: The scores of SS are in a geometric progression. Let S1=aS_1 = a and the common ratio of the geometric progression be rr:
    • S2=arS_2 = ar, S3=ar2S_3 = ar^2, S4=ar3S_4 = ar^3, S5=kS_5 = k

Step 2: Solve the equations

  1. From condition 3:
  2. From condition 5, the geometric progression stops at S5=kS_5 = k. For this to hold:

Step 3: Determine the values of aa and kk

Since scores range from 1 to 4, we test values of kk and aa to satisfy all conditions. Let k=2k = 2:

a=2k=4 a = 2k = 4

Substitute a=4a = 4 and k=2k = 2 into the sequence:

  • S1=4,S2=ar=4×2ka=4×44=2S_1 = 4, S_2 = ar = 4 \times \frac{2k}{a} = 4 \times \frac{4}{4} = 2
  • S3=ar2=4,S4=ar3=2,S5=k=2S_3 = ar^2 = 4, S_4 = ar^3 = 2, S_5 = k = 2

Final Scores:

  • R=[4,2,2,2,2,2,2,2]R = [4, 2, 2, 2, 2, 2, 2, 2]
  • S=[4,2,4,2,2,2,2,2]S = [4, 2, 4, 2, 2, 2, 2, 2]

Verification:

  1. R1+R2+R3=4+2+2=8R_1 + R_2 + R_3 = 4 + 2 + 2 = 8, S1+S2=4+4=8S_1 + S_2 = 4 + 4 = 8. Condition satisfied.
  2. SS forms a geometric progression for S1,S2,S3,S4S_1, S_2, S_3, S_4. Condition satisfied.
  3. From the fifth test onwards, S5=R5=2S_5 = R_5 = 2. Condition satisfied.
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