- The electron gain enthalpy of fluorine (\( \text{F} \)) is more negative than that of chlorine (\( \text{Cl} \)), so statement A is correct.
- Ionization enthalpy does decrease as we move down a group in the periodic table, so statement B is correct.
- Electronegativity of an atom is a property of the atom itself and does not depend on the atoms bonded to it, so statement C is incorrect.
- Al$_2$O$_3$ is amphoteric, but NO is a neutral oxide, not amphoteric, so statement D is also incorrect.
Thus, the incorrect statements are C and D.
Choose the correct option
Molecule | Shape | ||
---|---|---|---|
A | \(BrF_5\) | i | T-shape |
B | \(H_2O\) | ii | See-saw |
C | \(ClF_3\) | iii | Bent |
D | \(SF_4\) | iv | Square Pyramidal |
Match the following List-I with List-II and choose the correct option: List-I (Compounds) | List-II (Shape and Hybridisation) (A) PF\(_{3}\) (I) Tetrahedral and sp\(^3\) (B) SF\(_{6}\) (III) Octahedral and sp\(^3\)d\(^2\) (C) Ni(CO)\(_{4}\) (I) Tetrahedral and sp\(^3\) (D) [PtCl\(_{4}\)]\(^{2-}\) (II) Square planar and dsp\(^2\)
Let A be a 3 × 3 matrix such that \(\text{det}(A) = 5\). If \(\text{det}(3 \, \text{adj}(2A)) = 2^{\alpha \cdot 3^{\beta} \cdot 5^{\gamma}}\), then \( (\alpha + \beta + \gamma) \) is equal to: