The function \( f(x) = [x] + |x - 2| \) consists of two components:
1. The greatest integer function, \( [x] \), which has discontinuities at integer values of \( x \).
2. The absolute value function, \( |x - 2| \), which has a critical point at \( x = 2 \).
Now, consider the interval \( -2<x<3 \). The points where \( f(x) \) is not continuous or differentiable are determined by:
- Discontinuities in \( [x] \), which happen at \( x = -1, 0, 1, 2 \).
- A critical point in \( |x - 2| \) at \( x = 2 \).
So, the points where \( f(x) \) is not continuous are \( x = -1, 0, 1, 2 \), which gives us \( m = 4 \) discontinuities. The points where \( f(x) \) is not differentiable are due to the change in the slope at these points. Specifically, the function is not differentiable at \( x = 2 \), so \( n = 1 \).
Thus, \( m + n = 4 + 3 = 7 \).
Final Answer: \( m + n = 7 \).
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to: