The function \( f(x) = [x] + |x - 2| \) consists of two components:
1. The greatest integer function, \( [x] \), which has discontinuities at integer values of \( x \).
2. The absolute value function, \( |x - 2| \), which has a critical point at \( x = 2 \).
Now, consider the interval \( -2<x<3 \). The points where \( f(x) \) is not continuous or differentiable are determined by:
- Discontinuities in \( [x] \), which happen at \( x = -1, 0, 1, 2 \).
- A critical point in \( |x - 2| \) at \( x = 2 \).
So, the points where \( f(x) \) is not continuous are \( x = -1, 0, 1, 2 \), which gives us \( m = 4 \) discontinuities. The points where \( f(x) \) is not differentiable are due to the change in the slope at these points. Specifically, the function is not differentiable at \( x = 2 \), so \( n = 1 \).
Thus, \( m + n = 4 + 3 = 7 \).
Final Answer: \( m + n = 7 \).
Let \( f : [1, \infty) \to [2, \infty) \) be a differentiable function. If
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