Choose the correct option
Molecule Shape
A \(BrF_5\) i T-shape B \(H_2O\) ii See-saw C \(ClF_3\) iii Bent D \(SF_4\) iv Square Pyramidal
Choose the correct option
| Molecule | Shape | ||
|---|---|---|---|
| A | \(BrF_5\) | i | T-shape |
| B | \(H_2O\) | ii | See-saw |
| C | \(ClF_3\) | iii | Bent |
| D | \(SF_4\) | iv | Square Pyramidal |
- (A)- IV, (B)- III, (C)- I, (D)- II
- (A)- III, (B)- IV, (C)- I, (D)- II
- (A)- II, (B)- I, (C)- III, (D)- IV
- (A)- I, (B)- III, (C)- IV, (D)- II
The Correct Option is A
Solution and Explanation
Analyze Each Molecule Based on VSEPR Theory:
BrF5: The molecule has five bonded pairs and one lone pair around bromine, leading to a square pyramidal shape.
H2O: Water has two bonded pairs and two lone pairs, giving it a bent shape.
ClF3: Chlorine trifluoride has three bonded pairs and two lone pairs, resulting in a T-shape.
SF4: Sulfur tetrafluoride has four bonded pairs and one lone pair, leading to a see-saw shape.
Match Each Molecule with the Correct Shape:
(A) BrF5 - Square pyramidal
(B) H2O - Bent
(C) ClF3 - T-shape
(D) SF4 - See-saw
Conclusion: Based on the shapes identified above, the correct answer is Option (1).
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