Which of the following linear combinations of atomic orbitals will lead to the formation of molecular orbitals in homonuclear diatomic molecules (internuclear axis in z-direction)?
(1) \( 2p_z \) and \( 2p_x \)
(2) \( 2s \) and \( 2p_x \)
(3) \( 3d_{xy} \) and \( 3d_{x^2-y^2} \)
(4) \( 2s \) and \( 2p_z \)
(5) \( 2p_z \) and \( 3d_{x^2-y^2} \)
To determine which linear combinations of atomic orbitals will lead to the formation of molecular orbitals in homonuclear diatomic molecules with the internuclear axis in the z-direction, we need to consider the symmetry and orientation of the atomic orbitals involved.
Therefore, the correct choice is "D only," as only the combination of \(2s\) and \(2p_z\) leads to molecular orbital formation in the context described.
For molecular orbital formation along the z-direction, the atomic orbitals must have components along the z-axis.
The correct combination involves: - \( 2s \) and \( 2p_z \), both of which have components along the z-axis, and can combine effectively to form bonding and antibonding molecular orbitals.
Thus, the correct answer is \( \boxed{(3) D Only} \).
Regarding the molecular orbital (MO) energy levels for homonuclear diatomic molecules, the INCORRECT statement(s) is (are):
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 