18g
9g
The molar mass of water (H$_2$O) is calculated as: \[ \text{Molar mass of H}_2\text{O} = (2 \times 1) + (16) = 18 \, \text{g/mol} \] Now, we calculate the mass of 0.5 moles of water: \[ \text{Mass} = \text{Moles} \times \text{Molar mass} = 0.5 \, \text{mol} \times 18 \, \text{g/mol} = 9 \, \text{g} \] Thus, the mass of 0.5 moles of water is 9 g. So, the correct answer is option (2).
If 0.01 mol of $\mathrm{P_4O_{10}}$ is removed from 0.1 mol, then the remaining molecules of $\mathrm{P_4O_{10}}$ will be: