18g
9g
The molar mass of water (H$_2$O) is calculated as: \[ \text{Molar mass of H}_2\text{O} = (2 \times 1) + (16) = 18 \, \text{g/mol} \] Now, we calculate the mass of 0.5 moles of water: \[ \text{Mass} = \text{Moles} \times \text{Molar mass} = 0.5 \, \text{mol} \times 18 \, \text{g/mol} = 9 \, \text{g} \] Thus, the mass of 0.5 moles of water is 9 g. So, the correct answer is option (2).
Fortification of food with iron is done using $\mathrm{FeSO}_{4} .7 \mathrm{H}_{2} \mathrm{O}$. The mass in grams of the $\mathrm{FeSO}_{4} .7 \mathrm{H}_{2} \mathrm{O}$ required to achieve 12 ppm of iron in 150 kg of wheat is _______ (Nearest integer).} (Given : Molar mass of $\mathrm{Fe}, \mathrm{S}$ and O respectively are 56,32 and $16 \mathrm{~g} \mathrm{~mol}^{-1}$ )