Step 1: Identify the most important livestock in India. Cattle and buffaloes are considered the most important livestock in India, used for milk, meat, and agricultural purposes.
Step 2: Analyze the options. - Elephants, though culturally important, are not primarily used for milk or agricultural purposes.
- Dogs and cats are pets, not considered important livestock.
- Cattle and buffaloes are essential for agriculture, dairy, and meat production in India.
Conclusion: The correct answer is (B) Cattles and buffaloes.
| List I | List II | ||
|---|---|---|---|
| A | Rose | I | Twisted aestivation |
| B | Pea | II | Perigynous flower |
| C | Cotton | III | Drupe |
| D | Mango | IV | Marginal placentation |
| List I | List II | ||
|---|---|---|---|
| A | Robert May | I | Species-Area relationship |
| B | Alexander von Humboldt | II | Long term ecosystem experiment using out door plots |
| C | Paul Ehrlich | III | Global species diversity at about 7 million |
| D | David Tilman | IV | Rivet popper hypothesis |
At 15 atm pressure, $ \text{NH}_3(g) $ is being heated in a closed container from 27°C to 347°C and as a result, it partially dissociates following the equation: $ 2\text{NH}_3(g) \rightleftharpoons \text{N}_2(g) + 3\text{H}_2(g) $ If the volume of the container remains constant and pressure increases to 50 atm, then calculate the percentage dissociation of $ \text{NH}_3(g) $
If equilibrium constant for the equation $ A_2 + B_2 \rightleftharpoons 2AB \quad \text{is} \, K_p, $ then find the equilibrium constant for the equation $ AB \rightleftharpoons \frac{1}{2} A_2 + \frac{1}{2} B_2. $
Consider the following reaction: $ \text{CO}(g) + \frac{1}{2} \text{O}_2(g) \rightarrow \text{CO}_2(g) $ At 27°C, the standard entropy change of the process becomes -0.094 kJ/mol·K. Moreover, standard free energies for the formation of $ \text{CO}_2(g) $ and $ \text{CO}(g) $ are -394.4 and -137.2 kJ/mol, respectively. Predict the nature of the above chemical reaction.