Question:

Two soap bubbles of radius 2 cm and 4 cm, respectively, are in contact with each other. The radius of curvature of the common surface, in cm, is _______________.

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The radius of curvature of the common surface of two soap bubbles in contact is calculated using the formula r=r1r2r1r2 r = \frac{r_1 \cdot r_2}{r_1 - r_2} .
Updated On: Mar 18, 2025
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Correct Answer: 4

Solution and Explanation

For two soap bubbles in contact, the radius of curvature r r of the common surface is given by: r=r1r2r1r2 r = \frac{r_1 \cdot r_2}{r_1 - r_2} where r1=4cm r_1 = 4 \, \text{cm} and r2=2cm r_2 = 2 \, \text{cm} : r=2×442=82=4cm r = \frac{2 \times 4}{4 - 2} = \frac{8}{2} = 4 \, \text{cm} Thus, the answer is 4 \boxed{4} .
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