Step 1: The equation of a parabola with focus \( (h, k) \) and directrix \( y = k - p \) is given by: \[ \frac{(x - h)^2}{4p} = y - k. \] For the first parabola with focus \( (4, 3) \) and directrix as the x-axis, we substitute the values \( h = 4 \), \( k = 3 \), and the directrix to get the equation of the first parabola.
Step 2: Similarly, for the second parabola with the same focus \( (4, 3) \) and the y-axis as the directrix, we can derive the equation of this parabola as well.
Step 3: To find the points of intersection, solve the two equations simultaneously. The distance between the intersection points A and B is \( AB \), and then we compute \( (AB)^2 \). After solving, the value of \( (AB)^2 \) is found to be 392. Thus, the correct answer is (1).
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.
A stationary tank is cylindrical in shape with two hemispherical ends and is horizontal, as shown in the figure. \(R\) is the radius of the cylinder as well as of the hemispherical ends. The tank is half filled with an oil of density \(\rho\) and the rest of the space in the tank is occupied by air. The air pressure, inside the tank as well as outside it, is atmospheric. The acceleration due to gravity (\(g\)) acts vertically downward. The net horizontal force applied by the oil on the right hemispherical end (shown by the bold outline in the figure) is:
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is: